Thursday, May 21, 2020

Experiment on Newtons Second Law - 523 Words

Newtons Laws For this you will experiment with a simulated wagon, or sled (Fendt, W. (2003). Newton second law experiments. Retrieved on March 1, 2008, from HYPERLINK http://www.walter-fendt.de/ph14e/n2law.htm _blank http://www.walter-fendt.de:80/ph14e/n2law.htm ). The experiment is set up so that you can change the mass of the sled, the value of the hanging mass, and the coefficient of friction between the sled and the surface supporting it. The Experiment The mass of the wagon (M) and the hanging mass (m) are in kilograms. The total mass of the system is Mt, the sum of M and m. The acceleration of gravity (g) is 9.8 m/s2 . The acceleration of the system (a) varies, depending upon the experimental values of M, m, and  µ. In the situation shown above (ÃŽ ¼ = 0), the only force acting on the system is the weight of the hanging mass, Wm. Fill in the following table, using the value of a obtained from the simulation. Record and calculate data to the nearest three decimal places. The masses in the table are in kg, but the input data are in grams, so make the necessary conversions. The first row has been completed for you. M m a Wm Mt (Mt)a .100 .01 .892 .098 .11 .098 .100 .03 2.264 .294 .13 .294 .100 .05 3.270 .490 .15 .490 .100 .07 4.039 .686 .17 .687 .100 .10 4.905 .980 .2 .981 Used the following work to get results for the table: Wm=m* 9.8ms2 Wm=.03* 9.8m/s2= .294 Wm=.05* 9.8m/s2= .490 Wm=.07* 9.8m/s2= .686 Wm=.1* 9.8m/s2= .980 Mt= M +m Mt=Show MoreRelatedTrial And Prove Newton s Third Law1396 Words   |  6 Pagesthis experiment was to trial and prove Newton’s Third Law. Newton’s Third Law states for every action there is a reaction equal in magnitude and opposite in direction. In this experiment, by analyzing the difference of magnitudes of forces detected by the force sensors. This experiment consists three parts, each with different situations. Using the graphs, the forces were analyzed and used to determine whether the Newton’s Third law is valid. 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